5c^2-49c=0

Solution for 5c^2-49c=0 equation:

5c^2-49c=0

a = 5; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·5·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*5}=\frac{0}{10}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*5}=\frac{98}{10}
=9+4/5
$